If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+5-35=3x
We move all terms to the left:
x^2+5-35-(3x)=0
We add all the numbers together, and all the variables
x^2-3x-30=0
a = 1; b = -3; c = -30;
Δ = b2-4ac
Δ = -32-4·1·(-30)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{129}}{2*1}=\frac{3-\sqrt{129}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{129}}{2*1}=\frac{3+\sqrt{129}}{2} $
| 4Ix=3I=20 | | x+73(x-11)=180 | | 5u^2+46u+9=0 | | 5x+4/x+6=0 | | 5d^2+11d+6=0 | | 105+9.50r=105+14.75 | | 2(3x-8=4(1/4x-8) | | h^2+18h+17=0 | | 3^(0.2x)=2.4 | | 105+9.50r=14.75 | | 3p^2+46p+15=0 | | 2n=15/4=10-9/4 | | -4/3x-1/2=2(1/6x=-4) | | 4u^2+49u+12=0 | | 8(2x+1)+4(2x+3)=44 | | n+(7)=-19 | | 6-⅓x=-1 | | n-(9)=-26 | | 8h^2+33h+4=0 | | 12x^2-2x-7=0 | | 3u^2-20u+12=0 | | 3(n+4)=24+2n | | .5x+6=16 | | 8s^2-18s-5=0 | | -0.5x+-1.2=-1 | | 3(n+12)=24+2n | | V^2-23v+22=0 | | 11x^2+16x-12=0 | | 3x+1.5=1x+5 | | 3c+6=14c+50 | | 98=x^2+20x | | 20d^2+41d+2=0 |